Solution

center

Solution

Solution steps
Rewrite in the form of the standard circle equation
Therefore the circle properties are:
And the center is:

Popular Examples

center x^2+y^2+14x-16y+64=0center center 2x^2-2x+2y^2+4y=-1center center 4x^2+4y^2-4x+2y+1=0center center x^2+2x+y^2-3=6center center x^2+y^2+14x-16y=87center

Frequently Asked Questions (FAQ)

  • What is the center (x+2)^2+(y-3)^2=16 ?

    The center (x+2)^2+(y-3)^2=16 is (-2,3)