What is (x-6)^2+(y-2)^2=3^2 ?

The solution to (x-6)^2+(y-2)^2=3^2 is Circle with (a,b)=(6,2),r=3

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(x-6)^2+(y-2)^2=3^2

(x - 6)^{2} + (y - 2)^{2} = 3^{2}

(a, b) = (6, 2), r = 3

Solution steps

(x - 6)^{2} + (y - 2)^{2} = 3^{2}

Rewrite

(x - 6)^{2} + (y - 2)^{2} = 3^{2}

in the form of the standard circle equation

(x - 6)^{2} + (y - 2)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (6, 2), r = 3

a^{2} + b^{2} = 31

a^{2} + b^{2} = 32

4 x^{2} + 4 y^{2} - 20 x - 12 y - 110 = 0

a^{2} + b^{2} = 35

x^{2} + y^{2} = x + 7 y

What is (x-6)^2+(y-2)^2=3^2 ?
The solution to (x-6)^2+(y-2)^2=3^2 is Circle with (a,b)=(6,2),r=3