What is X^2+Y^2-X=0 ?

The solution to X^2+Y^2-X=0 is Circle with (a,b)=(1/2 ,0),r= 1/2

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X^2+Y^2-X=0

X^{2} + Y^{2} - X = 0

(a, b) = (\frac{1}{2}, 0), r = \frac{1}{2}

Solution steps

X^{2} + Y^{2} - X = 0

Rewrite

X^{2} + Y^{2} - X = 0

in the form of the standard circle equation

(X - \frac{1}{2})^{2} + (Y - 0)^{2} = (\frac{1}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{2}, 0), r = \frac{1}{2}

(x - 5)^{2} + (y + 2)^{2} = 6

(x - 5)^{2} + (y + 2)^{2} = 8

(x + 7)^{2} + (y + 3)^{2} = 64

x^{2} + y^{2} = 35

16 x^{2} + 16 y^{2} - 8 x + 96 y - 639 = 0

What is X^2+Y^2-X=0 ?
The solution to X^2+Y^2-X=0 is Circle with (a,b)=(1/2 ,0),r= 1/2