What is 8^2=x^2+y^2 ?

The solution to 8^2=x^2+y^2 is Circle with (a,b)=(0,0),r=8

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8^2=x^2+y^2

8^{2} = x^{2} + y^{2}

(a, b) = (0, 0), r = 8

Solution steps

8^{2} = x^{2} + y^{2}

Rewrite

8^{2} = x^{2} + y^{2}

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 8

x^{2} + y^{2} = 54

X^{2} + Y^{2} - X = 0

(x - 5)^{2} + (y + 2)^{2} = 6

(x - 5)^{2} + (y + 2)^{2} = 8

(x + 7)^{2} + (y + 3)^{2} = 64

What is 8^2=x^2+y^2 ?
The solution to 8^2=x^2+y^2 is Circle with (a,b)=(0,0),r=8