What is x^2+(y-10)^2=225 ?

The solution to x^2+(y-10)^2=225 is Circle with (a,b)=(0,10),r=15

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x^2+(y-10)^2=225

x^{2} + (y - 10)^{2} = 225

(a, b) = (0, 10), r = 15

Solution steps

x^{2} + (y - 10)^{2} = 225

Rewrite

x^{2} + (y - 10)^{2} = 225

in the form of the standard circle equation

(x - 0)^{2} + (y - 10)^{2} = 1 5^{2}

Therefore the circle properties are:

(a, b) = (0, 10), r = 15

2 x^{2} - 6 x + 2 y^{2} + 2 y - 45 = 0

(x + 2)^{2} + (y - 5)^{2} = 1

(x - 1)^{2} + (y + 3)^{2} = 4^{2}

(x + 1)^{2} + (y - 1)^{2} = 6^{2}

x^{2} + (y + 9)^{2} = 81

What is x^2+(y-10)^2=225 ?
The solution to x^2+(y-10)^2=225 is Circle with (a,b)=(0,10),r=15