What is (x+4)^2+(y+3)^2=9 ?

The solution to (x+4)^2+(y+3)^2=9 is Circle with (a,b)=(-4,-3),r=3

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(x+4)^2+(y+3)^2=9

(x + 4)^{2} + (y + 3)^{2} = 9

(a, b) = (- 4, - 3), r = 3

Solution steps

(x + 4)^{2} + (y + 3)^{2} = 9

Rewrite

(x + 4)^{2} + (y + 3)^{2} = 9

in the form of the standard circle equation

(x - (- 4))^{2} + (y - (- 3))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 4, - 3), r = 3

(x - 1)^{2} + (y - 2)^{2} = 123.21

x^{2} + y^{2} - 25 x - 25 y + 100 = 0

4 x^{2} + 4 y^{2} + 24 x - 32 y + 75 = 0

x^{2} + y^{2} - 3.11 x - 10.67 y - 62.22 = 0

x^{2} + y^{2} - 5 x = 12 - 6 y

What is (x+4)^2+(y+3)^2=9 ?
The solution to (x+4)^2+(y+3)^2=9 is Circle with (a,b)=(-4,-3),r=3