What is (y-2)^2+(x-8)^2=64 ?

The solution to (y-2)^2+(x-8)^2=64 is Circle with (a,b)=(8,2),r=8

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(y-2)^2+(x-8)^2=64

(y - 2)^{2} + (x - 8)^{2} = 64

(a, b) = (8, 2), r = 8

Solution steps

(y - 2)^{2} + (x - 8)^{2} = 64

Rewrite

(y - 2)^{2} + (x - 8)^{2} = 64

in the form of the standard circle equation

(x - 8)^{2} + (y - 2)^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (8, 2), r = 8

x^{2} + y^{2} - 18 x + 4 y + 60 = 0

x^{2} + y^{2} - 10 x - 16 y - 9 = 0

x^{2} + y^{2} = 17 - 16

x^{2} + y^{2} - 10 x + 20 y + 100 = 0

(x + 8)^{2} + (y + 6)^{2} = 100

What is (y-2)^2+(x-8)^2=64 ?
The solution to (y-2)^2+(x-8)^2=64 is Circle with (a,b)=(8,2),r=8