What is (x-2)^2+(y-6)^2=16 ?

The solution to (x-2)^2+(y-6)^2=16 is Circle with (a,b)=(2,6),r=4

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(x-2)^2+(y-6)^2=16

(x - 2)^{2} + (y - 6)^{2} = 16

(a, b) = (2, 6), r = 4

Solution steps

(x - 2)^{2} + (y - 6)^{2} = 16

Rewrite

(x - 2)^{2} + (y - 6)^{2} = 16

in the form of the standard circle equation

(x - 2)^{2} + (y - 6)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (2, 6), r = 4

(x - 3)^{2} + (y - 5)^{2} = 6^{2}

(x + \frac{54}{13})^{2} + (y - \frac{123}{26})^{2} = \frac{5165}{52}

(x + 3)^{2} + y^{2} = 48

(x - 4)^{2} + (y + 5)^{2} - 31 = 0

x^{2} + (y - 2)^{2} = 64

What is (x-2)^2+(y-6)^2=16 ?
The solution to (x-2)^2+(y-6)^2=16 is Circle with (a,b)=(2,6),r=4