What is x^2+(y-2)^2=64 ?

The solution to x^2+(y-2)^2=64 is Circle with (a,b)=(0,2),r=8

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x^2+(y-2)^2=64

x^{2} + (y - 2)^{2} = 64

(a, b) = (0, 2), r = 8

Solution steps

x^{2} + (y - 2)^{2} = 64

Rewrite

x^{2} + (y - 2)^{2} = 64

in the form of the standard circle equation

(x - 0)^{2} + (y - 2)^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (0, 2), r = 8

x^{2} + y^{2} - 9 x + 4 y - 13 = 0

(x - 15)^{2} + (y - 2)^{2} = 9

x^{2} + x + y^{2} + y = 4

(x - 4)^{2} + (y - 3)^{2} = 2 [(x + 2)^{2} + (y - 1)^{2}]

x^{2} + y^{2} + 2 x - 4 y = 11

What is x^2+(y-2)^2=64 ?
The solution to x^2+(y-2)^2=64 is Circle with (a,b)=(0,2),r=8