What is 2x^2+2y^2+15x+15y-15=0 ?

The solution to 2x^2+2y^2+15x+15y-15=0 is Circle with (a,b)=(-15/4 ,-15/4),r=(sqrt(285))/(2sqrt(2))

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2x^2+2y^2+15x+15y-15=0

2 x^{2} + 2 y^{2} + 15 x + 15 y - 15 = 0

(a, b) = (- \frac{15}{4}, - \frac{15}{4}), r = \frac{285}{2 2}

Solution steps

2 x^{2} + 2 y^{2} + 15 x + 15 y - 15 = 0

Rewrite

2 x^{2} + 2 y^{2} + 15 x + 15 y - 15 = 0

in the form of the standard circle equation

(x - (- \frac{15}{4}))^{2} + (y - (- \frac{15}{4}))^{2} = (\frac{285}{2 2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{15}{4}, - \frac{15}{4}), r = \frac{285}{2 2}

(x - 2)^{(2)} + (y + 1)^{(2)} \geq 4

(x - 2)^{2} + (y - 6)^{2} = 16

(x - 3)^{2} + (y - 5)^{2} = 6^{2}

(x + \frac{54}{13})^{2} + (y - \frac{123}{26})^{2} = \frac{5165}{52}

(x + 3)^{2} + y^{2} = 48

What is 2x^2+2y^2+15x+15y-15=0 ?
The solution to 2x^2+2y^2+15x+15y-15=0 is Circle with (a,b)=(-15/4 ,-15/4),r=(sqrt(285))/(2sqrt(2))