What is y^2+x^2+24x+10y+160=0 ?

The solution to y^2+x^2+24x+10y+160=0 is Circle with (a,b)=(-12,-5),r=3

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y^2+x^2+24x+10y+160=0

y^{2} + x^{2} + 24 x + 10 y + 160 = 0

(a, b) = (- 12, - 5), r = 3

Solution steps

y^{2} + x^{2} + 24 x + 10 y + 160 = 0

Rewrite

y^{2} + x^{2} + 24 x + 10 y + 160 = 0

in the form of the standard circle equation

(x - (- 12))^{2} + (y - (- 5))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 12, - 5), r = 3

What is y^2+x^2+24x+10y+160=0 ?
The solution to y^2+x^2+24x+10y+160=0 is Circle with (a,b)=(-12,-5),r=3