What is (x-2)^2+(y-1.5)^2=9 ?

The solution to (x-2)^2+(y-1.5)^2=9 is Circle with (a,b)=(2,1.5),r=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-2)^2+(y-1.5)^2=9

(x - 2)^{2} + (y - 1.5)^{2} = 9

(a, b) = (2, 1.5), r = 3

Solution steps

(x - 2)^{2} + (y - 1.5)^{2} = 9

Rewrite

(x - 2)^{2} + (y - 1.5)^{2} = 9

in the form of the standard circle equation

(x - 2)^{2} + (y - 1.5)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (2, 1.5), r = 3

x^{2} + y^{2} + 2 x + 4 y - 31 = 0

x^{2} + y^{2} + 10 x - 2 y - 23 = 0

(x - 6)^{2} + (y - 3)^{2} = 20^{2}

(x - 13)^{2} + (y + 7)^{2} = 144

x^{2} + (y - \frac{1}{4})^{2} = \frac{16}{9}

What is (x-2)^2+(y-1.5)^2=9 ?
The solution to (x-2)^2+(y-1.5)^2=9 is Circle with (a,b)=(2,1.5),r=3