What is (x+3)^2+(y+5)^2=5 ?

The solution to (x+3)^2+(y+5)^2=5 is Circle with (a,b)=(-3,-5),r=sqrt(5)

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(x+3)^2+(y+5)^2=5

(x + 3)^{2} + (y + 5)^{2} = 5

(a, b) = (- 3, - 5), r = 5

Solution steps

(x + 3)^{2} + (y + 5)^{2} = 5

Rewrite

(x + 3)^{2} + (y + 5)^{2} = 5

in the form of the standard circle equation

(x - (- 3))^{2} + (y - (- 5))^{2} = (5)^{2}

Therefore the circle properties are:

(a, b) = (- 3, - 5), r = 5

(x + 3)^{2} + (y + 5)^{2} = 3

3 = - 6 x + 4 y + x^{2} + y^{2}

(x + 2)^{2} + (y + 9)^{2} = 70

x^{2} + y^{2} - 8 x - 6 y = 20

x^{2} + y^{2} - 6 x + 6 y + 17 = 0

What is (x+3)^2+(y+5)^2=5 ?
The solution to (x+3)^2+(y+5)^2=5 is Circle with (a,b)=(-3,-5),r=sqrt(5)