What is 4x^2+4y^2=196 ?

The solution to 4x^2+4y^2=196 is Circle with (a,b)=(0,0),r=7

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4x^2+4y^2=196

4 x^{2} + 4 y^{2} = 196

(a, b) = (0, 0), r = 7

Solution steps

4 x^{2} + 4 y^{2} = 196

Rewrite

4 x^{2} + 4 y^{2} = 196

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 7

x^{2} + y^{2} - 3 x - 6 y + 9 = 0

4 x^{(2)} + 4 y^{(2)} - 56 x + 8 y + 56 = 0

100 - 25 x^{2} - 25 y^{2} = 0

(x + 8)^{2} + (y + 2)^{2} = 36

x^{2} - 2 x + y^{2} - 8 = 0

What is 4x^2+4y^2=196 ?
The solution to 4x^2+4y^2=196 is Circle with (a,b)=(0,0),r=7