What is ((x-2)^2)/(16)+((y+5)^2)/(16)=1 ?

The solution to ((x-2)^2)/(16)+((y+5)^2)/(16)=1 is Circle with (a,b)=(2,-5),r=4

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((x-2)^2)/(16)+((y+5)^2)/(16)=1

\frac{( x - 2 ) ^{2}}{16} + \frac{( y + 5 ) ^{2}}{16} = 1

(a, b) = (2, - 5), r = 4

Solution steps

\frac{( x - 2 ) ^{2}}{16} + \frac{( y + 5 ) ^{2}}{16} = 1

Rewrite

\frac{( x - 2 ) ^{2}}{16} + \frac{( y + 5 ) ^{2}}{16} = 1

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 5))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (2, - 5), r = 4

x^{2} - 2 x + 1 + y^{2} + y + \frac{1}{2} = \frac{11}{4}

x^{2} + 2 x + y^{2} - 2 y - 45 = 0

4 - (y - 4)^{2} = (x^{2} + 6 x + 9)

z^{2} + y^{2} = 9^{2}

x^{2} - 12 x + y^{2} - 2 y - 12 = 0

What is ((x-2)^2)/(16)+((y+5)^2)/(16)=1 ?
The solution to ((x-2)^2)/(16)+((y+5)^2)/(16)=1 is Circle with (a,b)=(2,-5),r=4