What is x^2+2x+y^2-6y=-7 ?

The solution to x^2+2x+y^2-6y=-7 is Circle with (a,b)=(-1,3),r=sqrt(3)

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x^2+2x+y^2-6y=-7

x^{2} + 2 x + y^{2} - 6 y = - 7

(a, b) = (- 1, 3), r = 3

Solution steps

x^{2} + 2 x + y^{2} - 6 y = - 7

Rewrite

x^{2} + 2 x + y^{2} - 6 y = - 7

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 3)^{2} = (3)^{2}

Therefore the circle properties are:

(a, b) = (- 1, 3), r = 3

4 x^{2} + 4 y^{2} + 4 x - 4 y + 1 = 0

2 x^{2} + 2 y^{2} + 16 - 40 = 0

(x + 5)^{2} + (y + 7)^{2} = 4

10 x^{2} + 10 y^{2} - 200 = 0

(x + 6)^{2} + (y + 14)^{2} = 100

What is x^2+2x+y^2-6y=-7 ?
The solution to x^2+2x+y^2-6y=-7 is Circle with (a,b)=(-1,3),r=sqrt(3)