What is 9(x-1)^2+9(y-9)^2=121 ?

The solution to 9(x-1)^2+9(y-9)^2=121 is Circle with (a,b)=(1,9),r= 11/3

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9(x-1)^2+9(y-9)^2=121

9 (x - 1)^{2} + 9 (y - 9)^{2} = 121

(a, b) = (1, 9), r = \frac{11}{3}

Solution steps

9 (x - 1)^{2} + 9 (y - 9)^{2} = 121

Rewrite

9 (x - 1)^{2} + 9 (y - 9)^{2} = 121

in the form of the standard circle equation

(x - 1)^{2} + (y - 9)^{2} = (\frac{11}{3})^{2}

Therefore the circle properties are:

(a, b) = (1, 9), r = \frac{11}{3}

x^{2} - 2 x + y^{2} - 6 y = 0

(x - (- 1))^{2} + (y - (- 3))^{2} = 16

x^{2} + y^{2} - 8 x + 6 y + 1 = 0

(x - 3)^{2} + (y + (- 1))^{2} = 16

x^{2} + 2 x + y^{2} - 6 y = - 7

What is 9(x-1)^2+9(y-9)^2=121 ?
The solution to 9(x-1)^2+9(y-9)^2=121 is Circle with (a,b)=(1,9),r= 11/3