What is x^2+y^2+12x-14y+36=0 ?

The solution to x^2+y^2+12x-14y+36=0 is Circle with (a,b)=(-6,7),r=7

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x^2+y^2+12x-14y+36=0

x^{2} + y^{2} + 12 x - 14 y + 36 = 0

(a, b) = (- 6, 7), r = 7

Solution steps

x^{2} + y^{2} + 12 x - 14 y + 36 = 0

Rewrite

x^{2} + y^{2} + 12 x - 14 y + 36 = 0

in the form of the standard circle equation

(x - (- 6))^{2} + (y - 7)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (- 6, 7), r = 7

x^{2} + y^{2} - 2 x - 6 y + \frac{1}{4} = 0

x^{2} + 16 x + y^{2} + 18 y = - 120

x^{2} + y^{2} - 12 x - 2 y + 12 = 0

x^{2} + y^{2} - 2 x + y = 5

3 x^{2} + 3 y^{2} + 2 x - 6 y - 4 = 0

What is x^2+y^2+12x-14y+36=0 ?
The solution to x^2+y^2+12x-14y+36=0 is Circle with (a,b)=(-6,7),r=7