What is x^2-11x+y^2+9y+15=0 ?

The solution to x^2-11x+y^2+9y+15=0 is Circle with (a,b)=(11/2 ,-9/2),r=sqrt(71/2)

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x^2-11x+y^2+9y+15=0

x^{2} - 11 x + y^{2} + 9 y + 15 = 0

(a, b) = (\frac{11}{2}, - \frac{9}{2}), r = \frac{71}{2}

Solution steps

x^{2} - 11 x + y^{2} + 9 y + 15 = 0

Rewrite

x^{2} - 11 x + y^{2} + 9 y + 15 = 0

in the form of the standard circle equation

(x - \frac{11}{2})^{2} + (y - (- \frac{9}{2}))^{2} = (\frac{71}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{11}{2}, - \frac{9}{2}), r = \frac{71}{2}

(x - 3)^{2} + (y - 7)^{2} = 52

4 x^{2} - 20 x + 4 y^{2} - 8 y = 7

36 x^{2} + 36 y^{2} - 48 x + 36 y - 119 = 0

x^{2} + y^{2} - 9 x + 4 y - 117 = 0

y^{2} + x^{2} - 16 x + 16 y + 92 = 0

What is x^2-11x+y^2+9y+15=0 ?
The solution to x^2-11x+y^2+9y+15=0 is Circle with (a,b)=(11/2 ,-9/2),r=sqrt(71/2)