What is 1=x^2+y^2-1 ?

The solution to 1=x^2+y^2-1 is Circle with (a,b)=(0,0),r=sqrt(2)

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1=x^2+y^2-1

1 = x^{2} + y^{2} - 1

(a, b) = (0, 0), r = 2

Solution steps

1 = x^{2} + y^{2} - 1

Rewrite

1 = x^{2} + y^{2} - 1

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (2)^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 2

(x + 16)^{2} + (y + 7)^{2} = 9

x^{2} + y^{2} + 6 x + 14 y + 49 = 0

\frac{( x + 2 ) ^{2}}{3} + \frac{z ^{2}}{3} = 3

x^{2} + y^{2} + 4 x - 6 y - 26 = 0

12 X^{2} + 12 Y^{2} = 144

What is 1=x^2+y^2-1 ?
The solution to 1=x^2+y^2-1 is Circle with (a,b)=(0,0),r=sqrt(2)