What is x^2+y^2-2x-8y+1=0 ?

The solution to x^2+y^2-2x-8y+1=0 is Circle with (a,b)=(1,4),r=4

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x^2+y^2-2x-8y+1=0

x^{2} + y^{2} - 2 x - 8 y + 1 = 0

(a, b) = (1, 4), r = 4

Solution steps

x^{2} + y^{2} - 2 x - 8 y + 1 = 0

Rewrite

x^{2} + y^{2} - 2 x - 8 y + 1 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - 4)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (1, 4), r = 4

What is x^2+y^2-2x-8y+1=0 ?
The solution to x^2+y^2-2x-8y+1=0 is Circle with (a,b)=(1,4),r=4