What is 4x^2+8x+4y^2-12y=23 ?

The solution to 4x^2+8x+4y^2-12y=23 is Circle with (a,b)=(-1, 3/2),r=3

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4x^2+8x+4y^2-12y=23

4 x^{2} + 8 x + 4 y^{2} - 12 y = 23

(a, b) = (- 1, \frac{3}{2}), r = 3

Solution steps

4 x^{2} + 8 x + 4 y^{2} - 12 y = 23

Rewrite

4 x^{2} + 8 x + 4 y^{2} - 12 y = 23

in the form of the standard circle equation

(x - (- 1))^{2} + (y - \frac{3}{2})^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 1, \frac{3}{2}), r = 3

What is 4x^2+8x+4y^2-12y=23 ?
The solution to 4x^2+8x+4y^2-12y=23 is Circle with (a,b)=(-1, 3/2),r=3