What is x^2=-y^2+10y+5 ?

The solution to x^2=-y^2+10y+5 is Circle with (a,b)=(0,5),r=sqrt(30)

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x^2=-y^2+10y+5

x^{2} = - y^{2} + 10 y + 5

(a, b) = (0, 5), r = 30

Solution steps

x^{2} = - y^{2} + 10 y + 5

Rewrite

x^{2} = - y^{2} + 10 y + 5

in the form of the standard circle equation

(x - 0)^{2} + (y - 5)^{2} = (30)^{2}

Therefore the circle properties are:

(a, b) = (0, 5), r = 30

What is x^2=-y^2+10y+5 ?
The solution to x^2=-y^2+10y+5 is Circle with (a,b)=(0,5),r=sqrt(30)