What is (x-4)^2+(y+11)^2=25 ?

The solution to (x-4)^2+(y+11)^2=25 is Circle with (a,b)=(4,-11),r=5

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(x-4)^2+(y+11)^2=25

(x - 4)^{2} + (y + 11)^{2} = 25

(a, b) = (4, - 11), r = 5

Solution steps

(x - 4)^{2} + (y + 11)^{2} = 25

Rewrite

(x - 4)^{2} + (y + 11)^{2} = 25

in the form of the standard circle equation

(x - 4)^{2} + (y - (- 11))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (4, - 11), r = 5

What is (x-4)^2+(y+11)^2=25 ?
The solution to (x-4)^2+(y+11)^2=25 is Circle with (a,b)=(4,-11),r=5