What is x^2+y^2-12x+27=0 ?

The solution to x^2+y^2-12x+27=0 is Circle with (a,b)=(6,0),r=3

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x^2+y^2-12x+27=0

x^{2} + y^{2} - 12 x + 27 = 0

(a, b) = (6, 0), r = 3

Solution steps

x^{2} + y^{2} - 12 x + 27 = 0

Rewrite

x^{2} + y^{2} - 12 x + 27 = 0

in the form of the standard circle equation

(x - 6)^{2} + (y - 0)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (6, 0), r = 3

What is x^2+y^2-12x+27=0 ?
The solution to x^2+y^2-12x+27=0 is Circle with (a,b)=(6,0),r=3