What is (x^2-4x)+(y^2-6y)=23 ?

The solution to (x^2-4x)+(y^2-6y)=23 is Circle with (a,b)=(2,3),r=6

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(x^2-4x)+(y^2-6y)=23

(x^{2} - 4 x) + (y^{2} - 6 y) = 23

(a, b) = (2, 3), r = 6

Solution steps

x^{2} - 4 x + (y^{2} - 6 y) = 23

Rewrite

x^{2} - 4 x + (y^{2} - 6 y) = 23

in the form of the standard circle equation

(x - 2)^{2} + (y - 3)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (2, 3), r = 6

What is (x^2-4x)+(y^2-6y)=23 ?
The solution to (x^2-4x)+(y^2-6y)=23 is Circle with (a,b)=(2,3),r=6