What is (x+7)^2+(y-4)^2=50 ?

The solution to (x+7)^2+(y-4)^2=50 is Circle with (a,b)=(-7,4),r=sqrt(50)

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(x+7)^2+(y-4)^2=50

(x + 7)^{2} + (y - 4)^{2} = 50

(a, b) = (- 7, 4), r = 50

Solution steps

(x + 7)^{2} + (y - 4)^{2} = 50

Rewrite

(x + 7)^{2} + (y - 4)^{2} = 50

in the form of the standard circle equation

(x - (- 7))^{2} + (y - 4)^{2} = (50)^{2}

Therefore the circle properties are:

(a, b) = (- 7, 4), r = 50

What is (x+7)^2+(y-4)^2=50 ?
The solution to (x+7)^2+(y-4)^2=50 is Circle with (a,b)=(-7,4),r=sqrt(50)