What is (x^2+4x)+(y^2+4y)=9 ?

The solution to (x^2+4x)+(y^2+4y)=9 is Circle with (a,b)=(-2,-2),r=sqrt(17)

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(x^2+4x)+(y^2+4y)=9

(x^{2} + 4 x) + (y^{2} + 4 y) = 9

(a, b) = (- 2, - 2), r = 17

Solution steps

x^{2} + 4 x + (y^{2} + 4 y) = 9

Rewrite

x^{2} + 4 x + (y^{2} + 4 y) = 9

in the form of the standard circle equation

(x - (- 2))^{2} + (y - (- 2))^{2} = (17)^{2}

Therefore the circle properties are:

(a, b) = (- 2, - 2), r = 17

What is (x^2+4x)+(y^2+4y)=9 ?
The solution to (x^2+4x)+(y^2+4y)=9 is Circle with (a,b)=(-2,-2),r=sqrt(17)