What is (x-2)^2+(y+9)^2=196 ?

The solution to (x-2)^2+(y+9)^2=196 is Circle with (a,b)=(2,-9),r=14

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(x-2)^2+(y+9)^2=196

(x - 2)^{2} + (y + 9)^{2} = 196

(a, b) = (2, - 9), r = 14

Solution steps

(x - 2)^{2} + (y + 9)^{2} = 196

Rewrite

(x - 2)^{2} + (y + 9)^{2} = 196

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 9))^{2} = 1 4^{2}

Therefore the circle properties are:

(a, b) = (2, - 9), r = 14

What is (x-2)^2+(y+9)^2=196 ?
The solution to (x-2)^2+(y+9)^2=196 is Circle with (a,b)=(2,-9),r=14