What is (x-9)^2+(y-8)^2=64 ?

The solution to (x-9)^2+(y-8)^2=64 is Circle with (a,b)=(9,8),r=8

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(x-9)^2+(y-8)^2=64

(x - 9)^{2} + (y - 8)^{2} = 64

(a, b) = (9, 8), r = 8

Solution steps

(x - 9)^{2} + (y - 8)^{2} = 64

Rewrite

(x - 9)^{2} + (y - 8)^{2} = 64

in the form of the standard circle equation

(x - 9)^{2} + (y - 8)^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (9, 8), r = 8

(x + \frac{1}{2})^{2} + (y - 5)^{2} = \frac{25}{4}

x^{2} + y^{2} - 4 x + 11 - 84 = 0

2 x^{2} + 2 y^{2} - 12 x + 4 y + 18 = 0

(x + 7)^{2} + y^{2} = 16

(x + 1)^{2} + (y - 1)^{2} = 9 (x - 2)^{2} + 9 (y + 1)^{2}

What is (x-9)^2+(y-8)^2=64 ?
The solution to (x-9)^2+(y-8)^2=64 is Circle with (a,b)=(9,8),r=8