What is x^2+5x+y^2-7y= 247/16 ?

The solution to x^2+5x+y^2-7y= 247/16 is Circle with (a,b)=(-5/2 , 7/2),r=(sqrt(543))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+5x+y^2-7y= 247/16

x^{2} + 5 x + y^{2} - 7 y = \frac{247}{16}

(a, b) = (- \frac{5}{2}, \frac{7}{2}), r = \frac{543}{4}

Solution steps

x^{2} + 5 x + y^{2} - 7 y = \frac{247}{16}

Rewrite

x^{2} + 5 x + y^{2} - 7 y = \frac{247}{16}

in the form of the standard circle equation

(x - (- \frac{5}{2}))^{2} + (y - \frac{7}{2})^{2} = (\frac{543}{4})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{5}{2}, \frac{7}{2}), r = \frac{543}{4}

x^{2} + (y + 4)^{2} = 3

x^{2} + (y + 4)^{2} = 5

(x + 5)^{2} + (y - 2)^{2} = 25

x^{2} + y^{2} + 2 x + 6 y + 9 = 0

(x - 15)^{2} + (y + 20)^{2} = (9)^{2}

What is x^2+5x+y^2-7y= 247/16 ?
The solution to x^2+5x+y^2-7y= 247/16 is Circle with (a,b)=(-5/2 , 7/2),r=(sqrt(543))/4