What is (x-9)^2+(y-12)^2=4(x^2+y^2) ?

The solution to (x-9)^2+(y-12)^2=4(x^2+y^2) is Circle with (a,b)=(-3,-4),r=10

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(x-9)^2+(y-12)^2=4(x^2+y^2)

(x - 9)^{2} + (y - 12)^{2} = 4 (x^{2} + y^{2})

(a, b) = (- 3, - 4), r = 10

Solution steps

(x - 9)^{2} + (y - 12)^{2} = 4 (x^{2} + y^{2})

Rewrite

(x - 9)^{2} + (y - 12)^{2} = 4 (x^{2} + y^{2})

in the form of the standard circle equation

(x - (- 3))^{2} + (y - (- 4))^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (- 3, - 4), r = 10

16 x^{2} + 16 y^{2} + 19 x - 40 y = 315

(x - 2)^{2} + (y - 4)^{2} = 1

x^{2} + 6 x + y^{2} - 7 = 0

x^{2} + 8 x + y^{2} - 4 y + 16 = 0

x^{2} + (y + 14. 5^{2} - 5^{2})^{2} = 14. 5^{2}

What is (x-9)^2+(y-12)^2=4(x^2+y^2) ?
The solution to (x-9)^2+(y-12)^2=4(x^2+y^2) is Circle with (a,b)=(-3,-4),r=10