What is (x+20)^2+(y-30)^2=225 ?

The solution to (x+20)^2+(y-30)^2=225 is Circle with (a,b)=(-20,30),r=15

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(x+20)^2+(y-30)^2=225

(x + 20)^{2} + (y - 30)^{2} = 225

(a, b) = (- 20, 30), r = 15

Solution steps

(x + 20)^{2} + (y - 30)^{2} = 225

Rewrite

(x + 20)^{2} + (y - 30)^{2} = 225

in the form of the standard circle equation

(x - (- 20))^{2} + (y - 30)^{2} = 1 5^{2}

Therefore the circle properties are:

(a, b) = (- 20, 30), r = 15

x^{2} + y^{2} + 14 x + 12 y = - 21

x^{2} + (y - 3)^{2} = 15

(x - 1)^{2} + (y + 8)^{2} = 4

x^{2} + y^{2} - 2 x - 4 y + 3 = 0

(x + 5)^{2} + (y - 4)^{2} = 16

What is (x+20)^2+(y-30)^2=225 ?
The solution to (x+20)^2+(y-30)^2=225 is Circle with (a,b)=(-20,30),r=15