What is y^2+4x-16-2y=-x^2 ?

The solution to y^2+4x-16-2y=-x^2 is Circle with (a,b)=(-2,1),r=sqrt(21)

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y^2+4x-16-2y=-x^2

y^{2} + 4 x - 16 - 2 y = - x^{2}

(a, b) = (- 2, 1), r = 21

Solution steps

y^{2} + 4 x - 16 - 2 y = - x^{2}

Rewrite

y^{2} + 4 x - 16 - 2 y = - x^{2}

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 1)^{2} = (21)^{2}

Therefore the circle properties are:

(a, b) = (- 2, 1), r = 21

(x + \frac{1}{9})^{2} + (y - \frac{2}{5})^{2} = 169

(x + 1.5)^{2} + (y - 1)^{2} = 0.5

4 = (x + 2)^{2} + (y - 1)^{2}

x^{2} + 4 x + y^{2} - 8 y = - 16

x^{2} + y^{2} + 2 x - 4 y = 44

What is y^2+4x-16-2y=-x^2 ?
The solution to y^2+4x-16-2y=-x^2 is Circle with (a,b)=(-2,1),r=sqrt(21)