What is 6(x-3)^2+6(y+7)^2=216 ?

The solution to 6(x-3)^2+6(y+7)^2=216 is Circle with (a,b)=(3,-7),r=6

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6(x-3)^2+6(y+7)^2=216

6 (x - 3)^{2} + 6 (y + 7)^{2} = 216

(a, b) = (3, - 7), r = 6

Solution steps

6 (x - 3)^{2} + 6 (y + 7)^{2} = 216

Rewrite

6 (x - 3)^{2} + 6 (y + 7)^{2} = 216

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 7))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (3, - 7), r = 6

(x + \frac{1}{2})^{2} + (y - \frac{4}{5})^{2} = \frac{9}{4}

x^{2} + 8 x + y^{2} - 2 y + 8 = 0

4 x^{2} + 4 y^{2} - 8 y - 21 = 0

x^{(2)} + y^{(2)} - 6 x - 8 y - 3 = 0

- 2 x^{2} - 36 x - 2 y^{2} - 122 = 0

What is 6(x-3)^2+6(y+7)^2=216 ?
The solution to 6(x-3)^2+6(y+7)^2=216 is Circle with (a,b)=(3,-7),r=6