What is (y+5/2)^2=-5(x-9/2) ?

The solution to (y+5/2)^2=-5(x-9/2) is Parabola with (h,k)=(9/2 ,-5/2),p=-5/4

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(y+5/2)^2=-5(x-9/2)

(y + \frac{5}{2})^{2} = - 5 (x - \frac{9}{2})

(h, k) = (\frac{9}{2}, - \frac{5}{2}), p = - \frac{5}{4}

Solution steps

(y + \frac{5}{2})^{2} = - 5 (x - \frac{9}{2})

Rewrite

(y + \frac{5}{2})^{2} = - 5 (x - \frac{9}{2})

in the standard form:

4 (- \frac{5}{4}) (x - \frac{9}{2}) = (y - (- \frac{5}{2}))^{2}

Therefore parabola properties are:

(h, k) = (\frac{9}{2}, - \frac{5}{2}), p = - \frac{5}{4}

(x - 2)^{2} = - 8 y

x + y^{2} = 5

x^{2} - 4 x - y + 3 = 0

y^{2} - 6 x - y + 11 = 0

x = (y + 1)^{2} + 3

What is (y+5/2)^2=-5(x-9/2) ?
The solution to (y+5/2)^2=-5(x-9/2) is Parabola with (h,k)=(9/2 ,-5/2),p=-5/4