What is x^2+y^2=3-y ?

The solution to x^2+y^2=3-y is Circle with (a,b)=(0,-1/2),r=(sqrt(13))/2

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x^2+y^2=3-y

x^{2} + y^{2} = 3 - y

(a, b) = (0, - \frac{1}{2}), r = \frac{13}{2}

Solution steps

x^{2} + y^{2} = 3 - y

Rewrite

x^{2} + y^{2} = 3 - y

in the form of the standard circle equation

(x - 0)^{2} + (y - (- \frac{1}{2}))^{2} = (\frac{13}{2})^{2}

Therefore the circle properties are:

(a, b) = (0, - \frac{1}{2}), r = \frac{13}{2}

x^{2} + y^{2} - 8 x + 10 y + 37 = 0

x^{2} + y^{2} = 1753

x^{2} + y^{2} + 4 y - 4 = 0

(x + 8)^{2} + (y + 6)^{2} = 400

x^{2} + y^{2} + 6 x - 8 y = 3

What is x^2+y^2=3-y ?
The solution to x^2+y^2=3-y is Circle with (a,b)=(0,-1/2),r=(sqrt(13))/2