What is x^2+y^2+12x+6y=7 ?

The solution to x^2+y^2+12x+6y=7 is Circle with (a,b)=(-6,-3),r=2sqrt(13)

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x^2+y^2+12x+6y=7

x^{2} + y^{2} + 12 x + 6 y = 7

(a, b) = (- 6, - 3), r = 213

Solution steps

x^{2} + y^{2} + 12 x + 6 y = 7

Rewrite

x^{2} + y^{2} + 12 x + 6 y = 7

in the form of the standard circle equation

(x - (- 6))^{2} + (y - (- 3))^{2} = (213)^{2}

Therefore the circle properties are:

(a, b) = (- 6, - 3), r = 213

x^{2} + y^{2} - 9 x + 4 y - 137 = 0

x^{2} + y^{2} - 2 x - 8 y + 1 + 16 - 7 = 0

x^{2} + y^{2} - 6 x - 6 y + 15 = 0

(x + 1)^{2} + (y + 4)^{2} = 4

x^{2} + y^{2} - 2 x - 2 y - 4 = 0

What is x^2+y^2+12x+6y=7 ?
The solution to x^2+y^2+12x+6y=7 is Circle with (a,b)=(-6,-3),r=2sqrt(13)