What is x^{(2)}+(y-3)^{(2)}=16 ?

The solution to x^{(2)}+(y-3)^{(2)}=16 is Circle with (a,b)=(0,3),r=4

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x^{(2)}+(y-3)^{(2)}=16

x^{(2)} + (y - 3)^{(2)} = 16

(a, b) = (0, 3), r = 4

Solution steps

x^{2} + (y - 3)^{2} = 16

Rewrite

x^{2} + (y - 3)^{2} = 16

in the form of the standard circle equation

(x - 0)^{2} + (y - 3)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (0, 3), r = 4

What is x^{(2)}+(y-3)^{(2)}=16 ?
The solution to x^{(2)}+(y-3)^{(2)}=16 is Circle with (a,b)=(0,3),r=4