What is x^2+y^2+6x-8y-11=0 ?

The solution to x^2+y^2+6x-8y-11=0 is Circle with (a,b)=(-3,4),r=6

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x^2+y^2+6x-8y-11=0

x^{2} + y^{2} + 6 x - 8 y - 11 = 0

(a, b) = (- 3, 4), r = 6

Solution steps

x^{2} + y^{2} + 6 x - 8 y - 11 = 0

Rewrite

x^{2} + y^{2} + 6 x - 8 y - 11 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 4)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (- 3, 4), r = 6

x^{2} + y^{2} - 8 x + 10 y - 88 = 0

\frac{x ^{2}}{5} + \frac{y ^{2}}{5} = 1

4 x^{2} + 4 y^{2} + 8 y - 45 = 0

x, h (x)^{2} + (8 - x)^{2} = 49

a^{2} + b^{2} = 7^{2}

What is x^2+y^2+6x-8y-11=0 ?
The solution to x^2+y^2+6x-8y-11=0 is Circle with (a,b)=(-3,4),r=6