What is (x+11)^2+(y+6)^2=324 ?

The solution to (x+11)^2+(y+6)^2=324 is Circle with (a,b)=(-11,-6),r=18

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(x+11)^2+(y+6)^2=324

(x + 11)^{2} + (y + 6)^{2} = 324

(a, b) = (- 11, - 6), r = 18

Solution steps

(x + 11)^{2} + (y + 6)^{2} = 324

Rewrite

(x + 11)^{2} + (y + 6)^{2} = 324

in the form of the standard circle equation

(x - (- 11))^{2} + (y - (- 6))^{2} = 1 8^{2}

Therefore the circle properties are:

(a, b) = (- 11, - 6), r = 18

(x + 3)^{2} + (y - 2)^{2} = 1^{2}

(x - 1)^{2} + (y)^{2} = 1

x^{2} - 8 x + y^{2} + 12 y = - 43

x^{2} + y^{2} - 10 x + 26 y + 167 = 0

(x + 4)^{2} + (y + 1)^{2} = 9

What is (x+11)^2+(y+6)^2=324 ?
The solution to (x+11)^2+(y+6)^2=324 is Circle with (a,b)=(-11,-6),r=18