What is (y-3)^2+24(x+2)=0 ?

The solution to (y-3)^2+24(x+2)=0 is Parabola with (h,k)=(-2,3),p=-6

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(y-3)^2+24(x+2)=0

(y - 3)^{2} + 24 (x + 2) = 0

(h, k) = (- 2, 3), p = - 6

Solution steps

(y - 3)^{2} + 24 (x + 2) = 0

Rewrite

(y - 3)^{2} + 24 (x + 2) = 0

in the standard form:

4 (- 6) (x - (- 2)) = (y - 3)^{2}

Therefore parabola properties are:

(h, k) = (- 2, 3), p = - 6

x^{2} + 18 x - 8 y + 81 = 0

(y + 5)^{2} = 5 x

x^{2} - 6 x + 24 y - 39 = 0

3 y^{2} - 30 y + 2 x + \frac{101}{2} = 0

y^{2} - 2 y = x

What is (y-3)^2+24(x+2)=0 ?
The solution to (y-3)^2+24(x+2)=0 is Parabola with (h,k)=(-2,3),p=-6