What is (x+3)^2+(y-4)^2=75 ?

The solution to (x+3)^2+(y-4)^2=75 is Circle with (a,b)=(-3,4),r=sqrt(75)

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(x+3)^2+(y-4)^2=75

(x + 3)^{2} + (y - 4)^{2} = 75

(a, b) = (- 3, 4), r = 75

Solution steps

(x + 3)^{2} + (y - 4)^{2} = 75

Rewrite

(x + 3)^{2} + (y - 4)^{2} = 75

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 4)^{2} = (75)^{2}

Therefore the circle properties are:

(a, b) = (- 3, 4), r = 75

x^{2} + y^{2} - 4 x + 3 y = 0

x^{2} + y^{2} - 6 x + 4 y - 11 = 0

74 = (24 - x)^{2} + (22 - y)^{2}

(x + 1)^{2} + (y - 1)^{2} = 9 ((x - 2)^{2} + (y + 1)^{2})

x^{2} + y^{2} - 15 = y + 2 x

What is (x+3)^2+(y-4)^2=75 ?
The solution to (x+3)^2+(y-4)^2=75 is Circle with (a,b)=(-3,4),r=sqrt(75)