What is 2(x-5)^2+2y^2=32 ?

The solution to 2(x-5)^2+2y^2=32 is Circle with (a,b)=(5,0),r=4

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2(x-5)^2+2y^2=32

2 (x - 5)^{2} + 2 y^{2} = 32

(a, b) = (5, 0), r = 4

Solution steps

2 (x - 5)^{2} + 2 y^{2} = 32

Rewrite

2 (x - 5)^{2} + 2 y^{2} = 32

in the form of the standard circle equation

(x - 5)^{2} + (y - 0)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (5, 0), r = 4

What is 2(x-5)^2+2y^2=32 ?
The solution to 2(x-5)^2+2y^2=32 is Circle with (a,b)=(5,0),r=4