What is 96+32x+16x^2-96y+16y^2=0 ?

The solution to 96+32x+16x^2-96y+16y^2=0 is Circle with (a,b)=(-1,3),r=2

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96+32x+16x^2-96y+16y^2=0

96 + 32 x + 16 x^{2} - 96 y + 16 y^{2} = 0

(a, b) = (- 1, 3), r = 2

Solution steps

96 + 32 x + 16 x^{2} - 96 y + 16 y^{2} = 0

Rewrite

96 + 32 x + 16 x^{2} - 96 y + 16 y^{2} = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 3)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- 1, 3), r = 2

x^{2} + y^{2} + 4 x + 6 y = 23

(x - 6)^{2} + y^{2} = 15

(x - 6)^{2} + y^{2} = 36

(x - 5)^{2} + (y + 0)^{2} = 29

(x - 2)^{2} + y^{2} = 5

What is 96+32x+16x^2-96y+16y^2=0 ?
The solution to 96+32x+16x^2-96y+16y^2=0 is Circle with (a,b)=(-1,3),r=2