What is x^2+(y-8)^2=81 ?

The solution to x^2+(y-8)^2=81 is Circle with (a,b)=(0,8),r=9

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x^2+(y-8)^2=81

x^{2} + (y - 8)^{2} = 81

(a, b) = (0, 8), r = 9

Solution steps

x^{2} + (y - 8)^{2} = 81

Rewrite

x^{2} + (y - 8)^{2} = 81

in the form of the standard circle equation

(x - 0)^{2} + (y - 8)^{2} = 9^{2}

Therefore the circle properties are:

(a, b) = (0, 8), r = 9

(x - 4)^{2} + (y - 4)^{2} = 9

(x - 4)^{2} + (y - 4)^{2} = 5

4 x^{2} + 4 y^{2} - 4 x + 12 y - 71 = 0

x, x^{2} + Y (x)^{2} = 64

2 x^{2} + 2 y^{2} + 16 x + 20 y + 18 = 0

What is x^2+(y-8)^2=81 ?
The solution to x^2+(y-8)^2=81 is Circle with (a,b)=(0,8),r=9