What is (x^2+y^2-4x-9)/4 =0 ?

The solution to (x^2+y^2-4x-9)/4 =0 is Circle with (a,b)=(2,0),r=sqrt(13)

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(x^2+y^2-4x-9)/4 =0

\frac{x ^{2} + y ^{2} - 4 x - 9}{4} = 0

(a, b) = (2, 0), r = 13

Solution steps

\frac{x ^{2} + y ^{2} - 4 x - 9}{4} = 0

Rewrite

\frac{x ^{2} + y ^{2} - 4 x - 9}{4} = 0

in the form of the standard circle equation

(x - 2)^{2} + (y - 0)^{2} = (13)^{2}

Therefore the circle properties are:

(a, b) = (2, 0), r = 13

What is (x^2+y^2-4x-9)/4 =0 ?
The solution to (x^2+y^2-4x-9)/4 =0 is Circle with (a,b)=(2,0),r=sqrt(13)