What is x^2+(y+4)^2=18 ?

The solution to x^2+(y+4)^2=18 is Circle with (a,b)=(0,-4),r=sqrt(18)

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x^2+(y+4)^2=18

x^{2} + (y + 4)^{2} = 18

(a, b) = (0, - 4), r = 18

Solution steps

x^{2} + (y + 4)^{2} = 18

Rewrite

x^{2} + (y + 4)^{2} = 18

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 4))^{2} = (18)^{2}

Therefore the circle properties are:

(a, b) = (0, - 4), r = 18

What is x^2+(y+4)^2=18 ?
The solution to x^2+(y+4)^2=18 is Circle with (a,b)=(0,-4),r=sqrt(18)