What is (x-8)^2+(y-4)^2=25 ?

The solution to (x-8)^2+(y-4)^2=25 is Circle with (a,b)=(8,4),r=5

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(x-8)^2+(y-4)^2=25

(x - 8)^{2} + (y - 4)^{2} = 25

(a, b) = (8, 4), r = 5

Solution steps

(x - 8)^{2} + (y - 4)^{2} = 25

Rewrite

(x - 8)^{2} + (y - 4)^{2} = 25

in the form of the standard circle equation

(x - 8)^{2} + (y - 4)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (8, 4), r = 5

x^{2} + y^{2} - 4 x + 10 y - 13 = 0

3 x^{2} + 3 y^{2} = 30

x^{2} + y^{2} - 2 x + 4 y - 8 = 0

(x - 7)^{2} + (y + 4)^{2} = 8

x^{2} + y^{2} + 3 y - \frac{7}{4} = 0

What is (x-8)^2+(y-4)^2=25 ?
The solution to (x-8)^2+(y-4)^2=25 is Circle with (a,b)=(8,4),r=5