What is 3x^2+3y^2=3 ?

The solution to 3x^2+3y^2=3 is Circle with (a,b)=(0,0),r=1

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3x^2+3y^2=3

3 x^{2} + 3 y^{2} = 3

(a, b) = (0, 0), r = 1

Solution steps

3 x^{2} + 3 y^{2} = 3

Rewrite

3 x^{2} + 3 y^{2} = 3

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 1

(x - 5)^{2} + (y - 5)^{2} = 100

x^{2} + y^{2} + \frac{20}{17} x - \frac{72}{17} y - \frac{912}{17} = 0

x^{2} + y^{2} + 4 x - 4 y - 32 = 0

72 = x^{2} + 6 x + 9 + y^{2} - 4 y + 4

(x + 6)^{2} + (y - 4)^{2} = 16

What is 3x^2+3y^2=3 ?
The solution to 3x^2+3y^2=3 is Circle with (a,b)=(0,0),r=1